4r^2-24=2r

Solution for 4r^2-24=2r equation:

4r^2-24=2r

We move all terms to the left:

4r^2-24-(2r)=0

a = 4; b = -2; c = -24;
Δ = b2-4ac
Δ = -22-4·4·(-24)
Δ = 388
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{388}=\sqrt{4*97}=\sqrt{4}*\sqrt{97}=2\sqrt{97}$
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2\sqrt{97}}{2*4}=\frac{2-2\sqrt{97}}{8}
$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2\sqrt{97}}{2*4}=\frac{2+2\sqrt{97}}{8}
$